How to define ordering when serializing object properties to JSON ?
Employ class
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | package test.albert.jackson; import lombok.Builder; import lombok.Data; @Data @Builder public class Employee { private Integer id; private String name; private String email; private String phone; private Address address; } |
Address class
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | package test.albert.jackson; import lombok.Builder; import lombok.Data; @Data @Builder public class Address { private String streetAddress; private String city; private String zipCode; } |
Using ObjectMapper to serialize object properties to JSON
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | package test.albert.jackson; import java.io.IOException; import com.fasterxml.jackson.databind.ObjectMapper; import lombok.extern.slf4j.Slf4j; @Slf4j public class JacksonTest { public static void main(String[] args) throws IOException { Address address = Address.builder().zipCode("110").city("台北市").streetAddress("信義區信義路五段7號").build(); Employee albert = Employee.builder().id(1).name("Albert").email("albert@gmail.com").phone("0900123456") .address(address).build(); ObjectMapper mapper = new ObjectMapper(); // convert object to JSON String json = mapper.writeValueAsString(albert); log.debug(json); } } |
How-to
You can make good use of @JsonPropertyOrder to define the ordering, for example
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 | package test.albert.jackson; import com.fasterxml.jackson.annotation.JsonPropertyOrder; import lombok.Builder; import lombok.Data; @Data @Builder @JsonPropertyOrder({ "id", "name", "address", "phone", "email" }) public class Employee { private Integer id; private String name; private String email; private String phone; private Address address; } |
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