Assume I have four exam type, each type has its passing scores.
I will provide a method, as people fill in exam type and scores, it will you tell you pass the exam or not.
This example will demonstrate how to use if / elif / else in Python program:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | """ 判斷分數是否通過考試 """ def passExan(examType, scores): if examType == '1': if scores >= 252.79: print("恭喜您通過 專業1→營運職2 升等考試") else: print("很抱歉,您未通過 專業1→營運職2 升等考試") elif examType == '2': if scores >= 248.65: print("恭喜您通過 專業2→專業1 升等考試") else: print("很抱歉,您未通過 專業2→專業1 升等考試") elif examType == '3': if scores >= 260.79: print("恭喜您通過 專業3→專業2 升等考試") else: print("很抱歉,您未通過 專業3→專業2 升等考試") elif examType == '4': if scores >= 254.88: print("恭喜您通過 專業4→專業3 升等考試") else: print("很抱歉,您未通過 專業4→專業3 升等考試") else: print("查無此考試項目") |
Test:
1 2 3 4 5 6 7 | Python 3.5.1 (v3.5.1:37a07cee5969, Dec 6 2015, 01:38:48) [MSC v.1900 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> import myUtil >>> myUtil.passExam("1", 270) 恭喜您通過 專業1→營運職2 升等考試 >>> myUtil.passExam("3", 180) 很抱歉,您未通過 專業3→專業2 升等考試 |
Reference
[1] http://www.tutorialspoint.com/python/python_if_else.htm
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